4y^2+17y+14=0

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Solution for 4y^2+17y+14=0 equation: 



4y^2+17y+14=0

a = 4; b = 17; c = +14;
Δ = b2-4ac
Δ = 172-4·4·14
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{65}}{2*4}=\frac{-17-\sqrt{65}}{8}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{65}}{2*4}=\frac{-17+\sqrt{65}}{8}
$

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